Specific volume of cylindrical virus par...

Specific volume of cylindrical virus particle is `6.02xx10^(-2)c c//g` , whose radius and length are `7Å and 10Å` respectively . If `N_(A)=6.023xx10^(23)` , find molecular weight of virus.

15.4 Kg/mol

`1.54 xx 10^4` Kg/mol

`3.08 xx 10^4` Kg/mol

`3.08 xx 10^3` Kg/mol

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