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A compound (60 gm) on analysis gave C=24...

A compound (60 gm) on analysis gave `C=24gm` H=4gm` and `O=32gm`, its empirical formula is

A

`CH_2 O_2`

B

`CH_2 O`

C

`CH_4 O`

D

`C_2 H_4 O_2`.

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