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To dissolve 0.9 g metal, 100 mL of 1 N H...

To dissolve 0.9 g metal, 100 mL of 1 N HCl is used. What is the equivalent weight of metal?

A

7

B

9

C

10

D

6

Text Solution

AI Generated Solution

The correct Answer is:
To find the equivalent weight of the metal, we can follow these steps: ### Step 1: Understand the concept of Normality Normality (N) is defined as the number of equivalents of solute per liter of solution. In this case, we have a 1 N solution of HCl. ### Step 2: Calculate the number of equivalents of HCl used Given that we have 100 mL of 1 N HCl, we can calculate the number of equivalents of HCl used: \[ \text{Number of equivalents of HCl} = \text{Normality} \times \text{Volume (in L)} \] \[ \text{Number of equivalents of HCl} = 1 \, \text{N} \times 0.1 \, \text{L} = 0.1 \, \text{equivalents} \] ### Step 3: Relate equivalents of HCl to the metal Since HCl is a strong acid and fully dissociates, 1 equivalent of HCl will react with 1 equivalent of metal. Therefore, the number of equivalents of the metal will also be 0.1 equivalents. ### Step 4: Calculate the equivalent weight of the metal The equivalent weight of a substance is defined as the mass of the substance that combines with or displaces 1 mole of hydrogen (or generates 1 gram of H2). The formula to calculate equivalent weight is: \[ \text{Equivalent weight} = \frac{\text{Mass of metal}}{\text{Number of equivalents}} \] Substituting the values we have: \[ \text{Equivalent weight} = \frac{0.9 \, \text{g}}{0.1 \, \text{equivalents}} = 9 \, \text{g/equiv} \] ### Conclusion The equivalent weight of the metal is 9 grams. ---
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