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In a reaction A+BhArrC+D the rate consta...

In a reaction `A+BhArrC+D` the rate constant of forward reaction & backward reaction is `K_(1)` and `K_(2)` then the equilibrium constant `(K)` for reaction is expressed as:

A

`K_(C)=(K_(2))/(K_(1))`

B

`K_(C)=(K_(1))/(K_(2))`

C

`K_(C)=K_(1)xxK_(2)`

D

`K_(C)=K_(1)+K_(2)`

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The correct Answer is:
To find the equilibrium constant \( K \) for the reaction \( A + B \rightleftharpoons C + D \) with given rate constants \( K_1 \) for the forward reaction and \( K_2 \) for the backward reaction, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reaction**: The reaction given is: \[ A + B \rightleftharpoons C + D \] Here, \( A \) and \( B \) are reactants, while \( C \) and \( D \) are products. 2. **Understand Rate Constants**: - The rate constant for the forward reaction (from reactants to products) is denoted as \( K_1 \). - The rate constant for the backward reaction (from products back to reactants) is denoted as \( K_2 \). 3. **Define the Equilibrium Constant**: The equilibrium constant \( K \) for a reaction at equilibrium is defined as the ratio of the rate of the forward reaction to the rate of the backward reaction: \[ K = \frac{R_F}{R_B} \] where \( R_F \) is the rate of the forward reaction and \( R_B \) is the rate of the backward reaction. 4. **Relate Rates to Rate Constants**: At equilibrium, the rate of the forward reaction is equal to the rate of the backward reaction. Therefore, we can express the rates in terms of the rate constants: \[ R_F = K_1 \cdot [A][B] \quad \text{(for forward reaction)} \] \[ R_B = K_2 \cdot [C][D] \quad \text{(for backward reaction)} \] However, at equilibrium, we can directly relate the rate constants to the equilibrium constant without needing to consider concentrations. 5. **Express the Equilibrium Constant**: Since \( K \) is defined as the ratio of the forward rate constant to the backward rate constant, we can write: \[ K = \frac{K_1}{K_2} \] ### Final Answer: Thus, the equilibrium constant \( K \) for the reaction \( A + B \rightleftharpoons C + D \) is expressed as: \[ K = \frac{K_1}{K_2} \]
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