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The melting point of RbBr is 682^(@) C w...

The melting point of RbBr is `682^(@)` C while that of NaF is `988^(@)` C The principal reason that the melting point of NaF is much higher than that of RbBr is that

A

The two crystals are not isomorphous

B

The molar mass of NaF is smaller than that of RbBr

C

The internuclear distance, `r_(c) + r_(a)` is greater for RbBr than for NaF

D

The bond in RbBr has more covalent character than the bond in NaF

Text Solution

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The correct Answer is:
C
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