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Fe(3)O(4) is:...

`Fe_(3)O_(4)` is:

A

Ferromagnetic

B

Diamagnetic

C

Paramagnetic

D

Ferrimagnetic

Text Solution

Verified by Experts

The correct Answer is:
D
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When steam is passed over hot iron, hydrogen is liberated and Fe_(3)O_(4) is formed according to the chemical equation 3 Fe + 4 H_(2)O to Fe_(3)O_(4) + 4 H_(2)(g) . In a typical reaction, 56 g iron was consumed. Calculate the following: The mass of Fe_(3)O_(4) formed. (R.A.M. : H = 1, O = 16, Fe = 56)

The oxidation state of Fe in Fe_(3)O_(8) is

0.7 g sample of iron ore was dissolved in acid. Iron was reduced to +2 state and it required 50 " mL of " (M)/(50) KMnO_(4) solution for titration. The percentage of Fe and Fe_(3)O_(4) in the ore is

Consider the following reactions. DeltaH^(@) values of the reactions hve been given as -x, -y and z kJ. Fe_(3)O_(4)(s) to 3Fe(s) + 2O_(2)(g), DeltaH^(@) = z kJ 2Fe(s) + O_(2)(g) to 2FeO(s), DeltaH^(@) =-x kJ 4Fe(s) + 3O_(2)(g) to 2Fe_(2)O_(3)(s), DeltaH^(@) =-y kJ Heat of reaction for the reaction, FeO(s) + Fe_(2)O_(3)(s) to Fe_(3)O_(4)(s) is :

0.804 g sample of iron ore was dissolved in acid. Iron was oxidised to +2 state and it requires 47.2 mL of 0.112N KMnO_(4) solution for titration, Calculate % of Fe of Fe_(3)O_(4) in ore.

1.5gm mixture of SiO_(2) and Fe_(2)O_(3) on very strong heating leave a residue weighting 1.46gm . The reaction responsible for loss of weight is . Fe_(2) O_(3) (s) rarr Fe_(3)O_(4) (s) + O_(2)(g) What is the percentage by mass of Fe_(2)O_(3) is original sample .

{:(List - I , List - II),((A)CaCO_(3) hArr CaO + CO_(3),(P) K_(p) = K_(c)),((B) NH_(4) HS hArr NH_(3)+ H_(2)S,(Q) "High pressure favours backward reaction"),((C) PCI_(5) hArr PCI_(3) + CI_(2),(R) K_(p) = K_(c) (RT)),((D) 3Fe(s) + 4H_(2) O(g) hArr Fe_(3) O_(4) (s) + 4H_(2)(g), (S) " Heterogeneous equilibrium "):}

Find the oxidation number of Fe in Fe_(3)O_(4)

W is the mass of iron (in g) which will be converted into Fe_(3)O_(4) by the action of 18 g of steam on it . What is the value of W/7 ? Fe+H_(2)O to Fe_(3)O_(4)+H_(2)

Balance the following equations by hit and trial method. Fe + H_(2)O to Fe_(3)O_(4) + H_(2)

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