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The percentage of free space in a body c...

The percentage of free space in a body centred cubic unit cell is

A

0.3

B

0.32

C

0.34

D

0.28

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The correct Answer is:
To find the percentage of free space in a body-centered cubic (BCC) unit cell, we can follow these steps: ### Step 1: Understand the Structure of BCC In a body-centered cubic unit cell, there are 2 atoms per unit cell (1 atom at the center and 8 corner atoms, each contributing 1/8 of an atom). ### Step 2: Calculate the Volume Occupied by Atoms The volume occupied by the atoms in the unit cell can be calculated using the formula for the volume of a sphere: \[ V_{\text{occupied}} = z \times \frac{4}{3} \pi r^3 \] where \( z = 2 \) for BCC. ### Step 3: Relate Radius (r) to Edge Length (a) In a BCC unit cell, the relationship between the radius \( r \) of the atom and the edge length \( a \) of the cube is given by: \[ r = \frac{\sqrt{3}}{4} a \] ### Step 4: Substitute Radius in the Volume Formula Substituting the expression for \( r \) into the volume formula: \[ V_{\text{occupied}} = 2 \times \frac{4}{3} \pi \left(\frac{\sqrt{3}}{4} a\right)^3 \] ### Step 5: Calculate the Total Volume of the Unit Cell The total volume of the unit cell is given by: \[ V_{\text{total}} = a^3 \] ### Step 6: Calculate Packing Efficiency Now, we can calculate the packing efficiency: \[ \text{Packing Efficiency} = \frac{V_{\text{occupied}}}{V_{\text{total}}} \] Substituting the values we calculated: \[ \text{Packing Efficiency} = \frac{2 \times \frac{4}{3} \pi \left(\frac{\sqrt{3}}{4} a\right)^3}{a^3} \] ### Step 7: Simplify the Expression After simplifying, we find: \[ \text{Packing Efficiency} = \frac{\sqrt{3} \pi}{8} \] ### Step 8: Calculate the Numerical Value of Packing Efficiency Calculating the numerical value: \[ \text{Packing Efficiency} \approx 0.68 \] ### Step 9: Calculate Free Space The free space in the unit cell can be calculated as: \[ \text{Free Space} = 100\% - \text{Packing Efficiency} \] \[ \text{Free Space} = 100\% - 68\% = 32\% \] ### Conclusion Thus, the percentage of free space in a body-centered cubic unit cell is **32%**. ---
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