The edge length of a cube is 400 pm. Its...

The edge length of a cube is 400 pm. Its body diagonal would be:

566 pm

600 pm

500 pm

693 pm

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

THE SOLID STATE
VMC MODULES ENGLISH|Exercise ILLUSTRATIONS|24 Videos
THE SOLID STATE
VMC MODULES ENGLISH|Exercise EXAMPLE|20 Videos
THE SOLID STATE
VMC MODULES ENGLISH|Exercise EFFICIENT|50 Videos
SURFACE CHEMISTRY
VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE|9 Videos
THEORY OF SOLUTIONS
VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|31 Videos

Similar Questions

Explore conceptually related problems

Edge length of cube is 300 pm. Its body diagonal would be:

If the unit cell edge length of NaCl crystal is 600 pm, then the density will be

KF has ccp structure. Calculate the radius of the unit cell if the edge length of the unit cell is 400 pm. How many F^(-) ions and octahedral voids are there in the unit cell ?

An ionic solid A^(o+)B^(Θ) crystallizes as an fcc structure. If the edge length of cell is 508 pm and the radius of anion is 144 pm , the radius of cation is

Polonium adopts cubic structure with edge length of cube being 0.336 nm. The distance of the body diagonal is

In a metal M having bcc arrangement edge length of the unit cell is 400 pm . The atomic radius of the metal is

A metal crystallises with a body-centred cubic lattice. The edge length of the unit cell is 360 pm. Radius of the metal atom is

What is the ratio of lengths of face edge, face diagonal and body diagonal of cube ?

The radius of Na^(+) is 95pm and that of Cl^(-) is 181 pm. The edge length of unit cell in NaCl would be (pm).

Caesium and chloride ions are in contact along the body diagonal in a body-centred cubic lattice. The edge lenth of the unit cell is 350 pm and Cs^+ has a radius of 133pm. Hence, the radius of Cl^- ion is approximately

VMC MODULES ENGLISH-THE SOLID STATE-IMPECCABLE

The percentage of free space in a body centred cubic unit cell is
Text Solution
|
With which one of the following elements silicon should be doped so as...
Text Solution
|
The edge length of a cube is 400 pm. Its body diagonal would be:
Text Solution
|
Explain how much portion of an atom located at (i) corner and (ii) bod...
Text Solution
|
In the calcium fluoride structure, the coodination number of the catio...
Text Solution
|
Copper crystallises in face-centred cubic lattice with a unit cell len...
Text Solution
|
Sodium crystallises in bcc arrangement with the interfacial separation...
Text Solution
|
Three element A,B,C crystallize into a cubic solid lattice.Atoms A occ...
Text Solution
|
A compound contains two types of atoms X and Y. it crystallises in a c...
Text Solution
|
AB crystallizes in a body centred cubic lattice with edge length 'a' e...
Text Solution
|
Total no. of voids in 0.5 mole of a compound forming hexagonal closed ...
Text Solution
|
Which of the following compounds is likely to show both Frenkel a...
Text Solution
|
A solid is formed by two elements P and Q . The element Q forms cubic ...
Text Solution
|
Structure of a mixed oxide is cubic close packed (ccp). The cubic unit...
Text Solution
|
The number of octahedral void(s) per atom present in a cubic close-pac...
Text Solution
|
A metal crystallizes with a face - centtered cubic lattice. The edge o...
Text Solution
|
A metal has a fcc lattice. The edge length of the unit cell is 404 pm....
Text Solution
|
The number of carbon atoms in a unit cell of diamond is:
Text Solution
|
If a is the length of the side of a cube, the distance between the bod...
Text Solution
|
A given metal crystallises out with a cubic structure having edge leng...
Text Solution
|