Ethylamine `underset ( Hg Cl _2 ) overset ( CS _2 ) to A overset( HOH ) to B [B ] ` is :

Options

A. Ethyl isothiocyanate
B. Ethyl isocyanide
C. Ethyl alcohol
D. Ethyl amine

Answer

To solve the problem, we need to follow the reactions step by step, starting with ethylamine and determining the products formed through the given reactions.

### Step 1: Reaction of Ethylamine with CH2 and HgCl2
1. **Starting Material**: Ethylamine (C2H5NH2).
2. **Reagents**: CH2 (methylene) and HgCl2 (mercury(II) chloride).
3. **Reaction Type**: This is a Hofmann mustard oil reaction.
4. **Mechanism**:
- The nitrogen in ethylamine has a lone pair of electrons and acts as a nucleophile.
- It attacks the electrophilic carbon in CH2, which is activated by HgCl2.
- This leads to the formation of ethyl isothiocyanate (C2H5N=C=S).

**Product A**: Ethyl isothiocyanate (C2H5N=C=S).

### Step 2: Hydrolysis of Product A
1. **Reagent**: Water (H2O).
2. **Reaction**: Hydrolysis of ethyl isothiocyanate.
3. **Mechanism**:
- The nitrogen in the isothiocyanate can be protonated by H+ from water.
- The carbon atom in the isothiocyanate is attacked by OH- from water.
- This leads to the formation of ethylamine and a byproduct of carbonyl sulfide (COS).

**Product B**: Ethylamine (C2H5NH2).

### Final Answer
Thus, the final product B is **ethylamine (C2H5NH2)**.

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