Methyl amine on reaction with Hinsberg reagent gives :

Options

A. N-methyl benzamide
B. N-methyl benzene sulphonamide
C. Methyl Isothiocyanata
D. N-methyl acetamide

Answer

To solve the question regarding the reaction of methyl amine with Hinsberg reagent, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are methyl amine (CH3NH2) and Hinsberg reagent (also known as benzene sulfonyl chloride, C6H5SO2Cl).

2. **Understand the Reaction Mechanism**:
- The Hinsberg reagent is used to differentiate between primary, secondary, and tertiary amines. When it reacts with primary and secondary amines, it forms sulfonamides.

3. **Write the Structure of Methyl Amine**:
- Methyl amine can be represented as:
\[ \text{H}_3C - \text{NH}_2 \]

4. **Write the Structure of Hinsberg Reagent**:
- The structure of the Hinsberg reagent (benzene sulfonyl chloride) is:
\[ \text{C}_6\text{H}_5 - \text{SO}_2 - \text{Cl} \]

5. **Reaction of Methyl Amine with Hinsberg Reagent**:
- When methyl amine reacts with the Hinsberg reagent, it forms a sulfonamide. The reaction involves the nucleophilic attack of the amine on the sulfonyl chloride, leading to the formation of N-methyl-benzenesulfonamide and the release of HCl.

6. **Write the Product**:
- The product formed from this reaction is:
\[ \text{C}_6\text{H}_5 - \text{SO}_2 - \text{NH}(\text{CH}_3) \]
- This compound is called N-methyl-benzenesulfonamide.

7. **Conclusion**:
- Therefore, the product formed when methyl amine reacts with Hinsberg reagent is **N-methyl-benzenesulfonamide**.

### Final Answer:
The correct answer is **N-methyl-benzenesulfonamide** (Option B).