When ethylamine is treated with sodium metal , the gas evoled is :

Options

A. `N_2`
B. `C_2 H_2`
C. `H_2`
D. `CO_2`

Answer

To solve the question "When ethylamine is treated with sodium metal, the gas evolved is:", we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are ethylamine (C2H5NH2) and sodium metal (Na).

### Step 2: Understand the Reaction
Sodium metal is a strong reducing agent. When it reacts with ethylamine, it can lead to the formation of an ionic compound and the release of hydrogen gas.

### Step 3: Write the Reaction
The reaction can be represented as follows:
\[ \text{C2H5NH2} + \text{Na} \rightarrow \text{C2H5NH}^- + \text{Na}^+ + \frac{1}{2} \text{H2} \]
In this reaction, ethylamine reacts with sodium to form an ethylamine anion and sodium cation, along with hydrogen gas.

### Step 4: Identify the Gas Evolved
From the reaction, we see that the byproduct is \(\frac{1}{2} \text{H2}\), which indicates that hydrogen gas (H2) is evolved during the reaction.

### Step 5: Compare with Given Options
The options provided are:
- A) N2
- B) C2H2
- C) H2
- D) CO2

Since we identified that hydrogen gas (H2) is evolved, the correct answer is option C.

### Final Answer
The gas evolved when ethylamine is treated with sodium metal is **H2 (hydrogen gas)**.

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