Ethylamine when treated with acetyl chloride we get a compound of the formula .

Options

A. `CH_3 - underset(O ) underset( ||) C-underset( CH_3) underset(|) N-NH -C_2H_5`
B. `C_2H_5 -underset(O) underset(||) C-NH -C_2 H_5`
C. `CH_3-underset(O) underset( ||)C- underset(H) underset(|) N-CH_2 -CH_3`
D. `CH_3 -underset(O) underset(||)C- underset(H) underset(|) N-underset(CH_3 ) underset( |) CH -CH_3`

Answer

To find the compound formed when ethylamine is treated with acetyl chloride, we can follow these steps:

### Step 1: Identify the Reactants
- Ethylamine has the formula **C2H5NH2** (or **CH3CH2NH2**).
- Acetyl chloride has the formula **CH3COCl**.

### Step 2: Understand the Reaction Mechanism
- Ethylamine contains a nitrogen atom with a lone pair of electrons, which makes it a nucleophile.
- Acetyl chloride has a carbonyl group (C=O) that is electrophilic due to the partial positive charge on the carbon atom (due to the electronegativity of oxygen).

### Step 3: Nucleophilic Attack
- The lone pair on the nitrogen atom of ethylamine attacks the electrophilic carbon atom of acetyl chloride.
- This results in the formation of a tetrahedral intermediate.

### Step 4: Formation of the Product
- The tetrahedral intermediate collapses, leading to the elimination of a chloride ion (Cl-), which is a good leaving group.
- This results in the formation of an amide.

### Step 5: Write the Final Product
- The product formed is **C2H5NHC(O)CH3**, which can also be written as **CH3C(O)NHC2H5**.
- This compound is known as N-ethylacetamide.

### Final Answer
The compound formed when ethylamine is treated with acetyl chloride is **C2H5NHC(O)CH3** or **N-ethylacetamide**.

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