Aniline ` underset( 50 ^@ C ) overset( H_2 O_2 ) to A ,[A] ` is :

Options

A. Nitrosobenzne
B. nitro aniline
C. aniline
D. phenol

Answer

To solve the question regarding the reaction of aniline with hydrogen peroxide (H₂O₂) at 50°C, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactant**:
- The reactant is aniline, which is represented as C₆H₅NH₂. It consists of a benzene ring (C₆H₅) attached to an amino group (NH₂).

2. **Understand the Reaction Conditions**:
- The reaction takes place in the presence of hydrogen peroxide (H₂O₂) at a temperature of 50°C. Hydrogen peroxide is a strong oxidizing agent.

3. **First Oxidation Step**:
- When aniline is treated with the first mole of H₂O₂, it undergoes oxidation to form N-phenyl hydroxyamine (C₆H₅NHOH). This compound has a hydroxyl group (-OH) attached to the nitrogen.

4. **Second Oxidation Step**:
- Upon further oxidation with the second mole of H₂O₂, N-phenyl hydroxyamine is converted to nitrosobenzene (C₆H₅NO). This involves the removal of two hydrogen atoms and the addition of a nitroso group (–NO).

5. **Final Oxidation Step**:
- With the third mole of H₂O₂, nitrosobenzene is oxidized to nitrobenzene (C₆H₅NO₂). This final step involves the addition of an oxygen atom to the benzene ring, resulting in the formation of the nitro group (–NO₂).

6. **Overall Reaction**:
- The overall reaction can be summarized as:
\[ \text{C₆H₅NH₂} + 3 \text{H₂O₂} \rightarrow \text{C₆H₅NO₂} + 4 \text{H₂O} \]
- Here, nitrobenzene is the final product, and four molecules of water are produced as by-products.

7. **Conclusion**:
- The product A formed from the reaction of aniline with H₂O₂ at 50°C is nitrobenzene (C₆H₅NO₂).

### Final Answer:
The product A is **Nitrobenzene (C₆H₅NO₂)**.

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