Write chemical reaction of aniline with benzoyl chloride and write the name of the product obtained.

Options

A. Schotten -Baumann reaction
B. Reimer -Tiemann reactionn
C. Wurtz -Fittig reaction
D. Wurtz reaction

Answer

To solve the question regarding the reaction of aniline with benzoyl chloride and to identify the product, we can follow these steps:

### Step 1: Identify the Reactants
- Aniline (C6H5NH2) is an aromatic amine with the formula C6H5NH2.
- Benzoyl chloride (C6H5COCl) is an acyl chloride derived from benzoic acid.

### Step 2: Write the Reaction
The reaction between aniline and benzoyl chloride can be represented as follows:

\[ \text{C}_6\text{H}_5\text{NH}_2 + \text{C}_6\text{H}_5\text{COCl} \rightarrow \text{C}_6\text{H}_5\text{N}(\text{C}_6\text{H}_5\text{CO}) + \text{HCl} \]

### Step 3: Mechanism of Reaction
1. The lone pair of electrons on the nitrogen atom of aniline attacks the carbon atom of the carbonyl group (C=O) in benzoyl chloride.
2. This forms a tetrahedral intermediate, which then collapses, leading to the formation of the amide and the release of hydrochloric acid (HCl).

### Step 4: Identify the Product
The product formed from this reaction is N-phenylbenzamide, which can be represented as:

\[ \text{C}_6\text{H}_5\text{N}(\text{C}_6\text{H}_5\text{CO}) \]

### Final Answer
The chemical reaction of aniline with benzoyl chloride produces N-phenylbenzamide, and the reaction can be summarized as:

\[ \text{Aniline} + \text{Benzoyl Chloride} \rightarrow \text{N-Phenylbenzamide} + \text{HCl} \]