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GABRIEL PHTHALIMIDE SYNTHESIS GIVES...

GABRIEL PHTHALIMIDE SYNTHESIS GIVES

A

`1^@ ` aliphatic amine

B

`2^@` aliphatic amine

C

`2^@ ` aromiatic amine

D

`1^@` aromatic amine

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The correct Answer is:
**Step-by-Step Solution: Gabriel Phthalimide Synthesis** 1. **Understanding the Reaction**: The Gabriel phthalimide synthesis is a method used to prepare primary amines. It involves the use of phthalimide and an alkyl halide. 2. **Formation of Potassium Phthalimide**: - Start with phthalimide, which has the structure: \[ \text{C}_6\text{H}_4(\text{CO} - \text{NH})_2 \] - Treat phthalimide with a strong base like potassium hydroxide (KOH). The base abstracts the acidic hydrogen from the nitrogen, resulting in the formation of potassium phthalimide: \[ \text{Phthalimide} + \text{KOH} \rightarrow \text{Potassium Phthalimide} + \text{H}_2\text{O} \] 3. **Alkylation**: - The potassium phthalimide is then reacted with an alkyl halide (e.g., CH₃Br). The nucleophilic nitrogen attacks the carbon of the alkyl halide, leading to the formation of N-alkyl phthalimide: \[ \text{Potassium Phthalimide} + \text{CH}_3\text{Br} \rightarrow \text{N-Methyl Phthalimide} + \text{KBr} \] 4. **Hydrolysis**: - The N-alkyl phthalimide undergoes hydrolysis (either acidic or basic) to yield the corresponding primary amine and phthalic acid: \[ \text{N-Methyl Phthalimide} + \text{H}_2\text{O} \rightarrow \text{Methylamine} + \text{Phthalic Acid} \] 5. **Final Product**: - The primary amine formed from this reaction is methylamine (CH₃NH₂), which is classified as a primary aliphatic amine. 6. **Conclusion**: - Therefore, the product of the Gabriel phthalimide synthesis is a primary aliphatic amine. **Final Answer**: The correct answer is **Primary Aliphatic Amine**. ---
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Assertion : Tert. Butyl amine can be formed by Gabriel phthalimide synthesis Reason : It follow S_(N)1 mechanism

Prepare R-NH2 by Gabriel synthesis .

Assertion (A) : Gabriel phthalimide reaction is used for the prepartion fo C_2H_5NH_2 and p-nitro aniline . Reason (R ): SN^2 reaction takes place with 1^@ RX and 1^@ ArX containing overline e - withdrawing group at o-and p-positions

Assertion : Aromatic primary amines can be prepared by Gabriel phthalimide synthesis . Reason : Aryl halides undergo uncelophilic substitution with the anion formed by phthalimide .

Statement 1: Aryl amines cannot be prepared by Gabriel's phthalimide synthesis and Statement 2: Aromatic halides do not give S_(N)2 reactions.

A: Aniline is not prepared by Gabriel phthalimide synthesis. R: Due to partial double bond character in haloarene because of resonance.

Explain the following reactions : (a) Gabriel Phthalimide reaction (b) Coupling reaction

(a) Write the reactions involved in the following : (i) Hofmann bromamide degradation reaction. (ii) Diazotisation . (iii) Gabriel phthalimide synthesis (b) Give reasons : (i) (CH_(3))_(2)NH is more basic than (CH_(3))_(3)N in an aqueous solution. (ii) Aromatic diazonium salts are more stable than aliphatic diazonium salts .

Assertion (A) Gabriel phthalimide reaction can be used to prepare aryl and alkyl amines. Reason (R ) Aryl halides have same reactivity as alkyl halides towards nucleophilic substitution reactions.

Assertion(A): Aromatic 1^(@ amines can be prepared by Gabriel phtalmide synthesis. Reason (R ): Aryl halides undergo nucleophilic substitution with anion formed by pthalimide.

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