Reaction of aniline with benzaldehyde is

Options

A. Benzoin
B. Azoxy benzene
C. Schiff's base
D. Unsaturated acid

Answer

To determine the product of the reaction between aniline and benzaldehyde, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- Aniline (C6H5NH2) is an aromatic amine where a benzene ring is attached to an amino group (NH2).
- Benzaldehyde (C6H5CHO) is an aromatic aldehyde where a benzene ring is attached to a carbonyl group (CHO).

2. **Understand the Reaction Mechanism**:
- When aniline reacts with benzaldehyde, the amino group (NH2) of aniline acts as a nucleophile and attacks the carbonyl carbon of benzaldehyde.
- This results in the formation of a tetrahedral intermediate.

3. **Elimination of Water**:
- The tetrahedral intermediate then undergoes dehydration (loss of water, H2O) to form a double bond between the nitrogen and the carbon of the former carbonyl group.
- The reaction can be summarized as:
\[ \text{C6H5NH2} + \text{C6H5CHO} \rightarrow \text{C6H5CH=N-C6H5} + \text{H2O} \]
- The product formed is a Schiff's base, which is characterized by the presence of a C=N double bond.

4. **Identify the Product**:
- The product from the reaction is a compound where the nitrogen is double-bonded to the carbon that was part of the carbonyl group of benzaldehyde. This compound can be represented as C6H5CH=N-C6H5, which is a Schiff's base.

5. **Conclusion**:
- Therefore, the reaction of aniline with benzaldehyde yields a Schiff's base.

### Final Answer:
The reaction of aniline with benzaldehyde is a Schiff's base.