Following reaction gives two products . Write the structures of the products .
` CH_3 CH_2 NH_2 overset ((CH_3CO)_2O, heat ) rarr`A + B

Answer

To solve the problem, we need to analyze the reaction between ethylamine (CH₃CH₂NH₂) and acetic anhydride ((CH₃CO)₂O) under heat. This reaction is known as acetylation, where an acyl group is added to the amine.

### Step-by-Step Solution:

1. **Identify Reactants**:
- The reactant is ethylamine (CH₃CH₂NH₂).
- The reagent is acetic anhydride ((CH₃CO)₂O).

2. **Understanding Acetylation**:
- In this reaction, the acetic anhydride donates an acyl group (CH₃C(=O)-) to the nitrogen atom of the amine. This process involves the nucleophilic attack of the nitrogen on the carbonyl carbon of the acetic anhydride.

3. **Draw the Structure of Acetic Anhydride**:
- Acetic anhydride has the structure:
```
O
||
CH₃C-O-C(=O)CH₃
```

4. **Nucleophilic Attack**:
- The nitrogen atom in ethylamine has a lone pair of electrons and acts as a nucleophile. It attacks the electron-deficient carbonyl carbon of the acetic anhydride.
- This results in the formation of a tetrahedral intermediate, where the nitrogen becomes positively charged and the oxygen of the carbonyl becomes negatively charged.

5. **Formation of Products**:
- The tetrahedral intermediate collapses, leading to the formation of an amide and the release of an acetate ion.
- The amide formed is N-ethylacetamide (CH₃CH₂NHCOCH₃).
- The acetate ion (CH₃COO⁻) is also produced.

6. **Final Products**:
- The two products from the reaction are:
- **A**: N-ethylacetamide (CH₃CH₂NHCOCH₃)
- **B**: Acetic acid (CH₃COOH)

### Structures of the Products:
- **A (N-ethylacetamide)**:
```
CH₃
|
CH₃C(=O)NHCH₂CH₃
```

- **B (Acetic acid)**:
```
CH₃
|
COOH
```

### Summary of Products:
- **Product A**: N-ethylacetamide (CH₃CH₂NHCOCH₃)
- **Product B**: Acetic acid (CH₃COOH)

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