The reduction of a nitrile by LiAlH_( 4 ) produes :

Options

A. Primary amine
B. Secondary amine
C. Tetiary amine
D. Amide

Answer

To solve the question regarding the reduction of a nitrile by LiAlH4, we can break down the process into several steps.

### Step-by-Step Solution:

1. **Understanding the Reactants**:
- A nitrile has the general formula \( R-C \equiv N \), where \( R \) is an alkyl or aryl group.
- Lithium aluminum hydride (LiAlH4) is a strong reducing agent that provides hydride ions (H-) for reduction reactions.

2. **Mechanism of Reduction**:
- When nitrile is treated with LiAlH4, the hydride ion from LiAlH4 acts as a nucleophile and attacks the electrophilic carbon atom of the nitrile.
- This leads to the formation of a tetrahedral intermediate.

3. **Formation of Imine**:
- The nucleophilic attack results in the formation of an intermediate that can rearrange to form an imine (R-C(=N)-H) and release a negative charge on nitrogen.

4. **Further Reduction**:
- The imine can be further reduced by another equivalent of LiAlH4, leading to the formation of a primary amine (R-CH2-NH2).

5. **Final Product**:
- Therefore, the overall reaction of nitrile with LiAlH4 results in the formation of a primary amine.

### Conclusion:
The reduction of a nitrile by LiAlH4 produces a primary amine.