`C_(6)H_(5)NH_(2) + CS_(2) underset(KOH (s))overset(Delta)rarr`
The end product in the reaction is

Options

A. Phenyl cyanide
B. Phenyl isocyanide
C. Phenyl isothiocyanate
D. p-Amino benzene sulphonic acid

Answer

To solve the question regarding the reaction of aniline (C₆H₅NH₂) with carbon disulfide (CS₂) in the presence of potassium hydroxide (KOH) and heat, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants are aniline (C₆H₅NH₂) and carbon disulfide (CS₂). Aniline is an aromatic amine with a phenyl group attached to an amino group.

2. **Understand the Reaction Conditions**:
The reaction occurs in the presence of potassium hydroxide (KOH) and is heated. KOH acts as a strong base, which will facilitate the reaction.

3. **Recognize the Type of Reaction**:
This reaction is known as the mustard oil reaction, which typically involves the reaction of an amine with carbon disulfide to form isothiocyanates.

4. **Write the Reaction**:
When aniline reacts with carbon disulfide in the presence of KOH, the following reaction occurs:
\[ C₆H₅NH₂ + CS₂ \xrightarrow{KOH, \Delta} C₆H₅N=C=S + H₂O + K₂S \]
Here, C₆H₅N=C=S is phenyl isothiocyanate.

5. **Identify the Product**:
The product formed is phenyl isothiocyanate (C₆H₅N=C=S), which is characterized by the presence of a sulfur atom in the isothiocyanate functional group.

6. **Conclusion**:
The end product of the reaction between aniline and carbon disulfide in the presence of KOH and heat is phenyl isothiocyanate.

### Final Answer:
The end product of the reaction is **phenyl isothiocyanate**.

---