Benzene diazonium chloride on reaction with phenol in weakly basic medium gives

Options

A. Diphenyl ether
B. p -Hydroxyazobenzene
C. Chlorobenzene
D. Benzene

Answer

To solve the question regarding the reaction of benzene diazonium chloride with phenol in a weakly basic medium, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are benzene diazonium chloride (C6H5N2Cl) and phenol (C6H5OH).
- Benzene diazonium chloride contains a diazonium group (-N2^+) which is a good electrophile.

2. **Understand the Reaction Conditions**:
- The reaction occurs in a weakly basic medium. This condition is important as it influences the reactivity of phenol and the position of substitution on the aromatic ring.

3. **Determine the Directing Effects**:
- The hydroxyl group (-OH) in phenol is an ortho- and para-directing group due to its electron-donating nature. This means that the electrophile (the diazonium ion) will preferentially attack the ortho or para positions of the phenol.

4. **Predict the Product**:
- Since the reaction occurs in a weakly basic medium, the diazonium ion will react with the phenol. The most likely product will be formed at the para position due to steric factors and the stability of the resulting product.
- The reaction leads to the formation of parahydroxyazobenzene, which has the structure C6H4(OH)-N=N-C6H5.

5. **Write the Final Product**:
- The final product of the reaction is parahydroxyazobenzene, which can be represented as C6H4(OH)-N=N-C6H5.

### Final Answer:
Benzene diazonium chloride on reaction with phenol in a weakly basic medium gives **parahydroxyazobenzene**.

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