`CH_(3)CH_(2)NH_(2) overset((CH_(3)CO)_(2))underset(Delta) to A+B`, (A) and (B) are

Options

A. `CH_3 CH_2 OH ,CH_3 CONH CH_2 CH_3`
B. `CH_3COOH ,CH_3 CH_2 NHCOCH_3 `
C. `CH_3 CH_2 COOH,CH_3 NHCOCH_3`
D. `CH_3COOH,CH_3 CONHCH_3`

Answer

To solve the question regarding the reaction of ethyl amine (CH₃CH₂NH₂) with acetic anhydride ((CH₃CO)₂O) to form products A and B, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Ethyl amine (CH₃CH₂NH₂)
- Acetic anhydride ((CH₃CO)₂O)

### Step 2: Understand the Reaction Mechanism
In this reaction, ethyl amine acts as a nucleophile due to the presence of the lone pair of electrons on the nitrogen atom. Acetic anhydride, with its carbonyl groups, acts as an electrophile because the carbonyl carbon is positively polarized.

### Step 3: Nucleophilic Attack
The nitrogen atom in ethyl amine attacks one of the carbonyl carbons in acetic anhydride. This leads to the formation of a tetrahedral intermediate. The oxygen atom in the carbonyl group will bear a negative charge due to the nucleophilic attack.

### Step 4: Bond Rearrangement
To stabilize the tetrahedral intermediate, one of the bonds between the carbonyl carbon and the oxygen will break. This results in the formation of a new bond between the nitrogen and the carbonyl carbon, leading to the formation of ethyl acetamide.

### Step 5: Proton Transfer
The negatively charged oxygen (from the carbonyl that was attacked) will abstract a proton (H⁺) from the solution, leading to the formation of acetic acid (CH₃COOH).

### Step 6: Identify the Products
After the reaction, we can identify the products:
- Product A: Ethyl acetamide (CH₃CH₂NHCOCH₃)
- Product B: Acetic acid (CH₃COOH)

### Final Answer
The products A and B from the reaction of ethyl amine with acetic anhydride are:
- A: Ethyl acetamide (CH₃CH₂NHCOCH₃)
- B: Acetic acid (CH₃COOH)

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