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A man suffering from haemophilia, marrie...

A man suffering from haemophilia, married a normal woman whose father was haemophilic. What is the expected pattern in their children ?

A

All son are affected but all daughters are normal

B

50% of sons and 50% of daughters are affected

C

All daughters are affected but all sons are normal

D

75% of the progeny is affected

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The correct Answer is:
To solve the problem of a man suffering from hemophilia marrying a normal woman whose father was hemophilic, we need to analyze the genetic inheritance pattern of hemophilia, which is an X-linked recessive disorder. ### Step-by-Step Solution: 1. **Identify the Genotypes**: - The man is hemophilic, which means he has the genotype X^H Y (where X^H represents the hemophilic allele). - The woman is normal but has a father who is hemophilic. This means she must carry one normal allele and one hemophilic allele, making her genotype X^H X (where X^H is the hemophilic allele inherited from her father and X is the normal allele). 2. **Determine Gametes**: - The man can produce two types of gametes: X^H (hemophilic) and Y (normal). - The woman can produce two types of gametes: X (normal) and X^H (hemophilic). 3. **Set Up a Punnett Square**: - Create a Punnett square to visualize the possible combinations of alleles from the parents: ``` X X^H ---------------- X^H | X^H X | X^H X^H | ---------------- Y | X Y | X^H Y | ---------------- ``` 4. **Analyze the Offspring**: - The potential genotypes of the offspring from the Punnett square are: - X^H X (female carrier) - X^H Y (affected male) - X X (normal female) - X Y (normal male) 5. **Determine the Phenotypes**: - From the genotypes: - X^H X: Carrier female (not affected) - X^H Y: Affected male - X X: Normal female - X Y: Normal male 6. **Calculate the Ratios**: - The offspring can be categorized as follows: - 1 affected male (X^H Y) - 1 carrier female (X^H X) - 1 normal female (X X) - 1 normal male (X Y) - This results in: - 50% of sons (1 out of 2) affected and 50% of daughters (1 out of 2) affected (1 carrier, 1 normal). 7. **Conclusion**: - The expected pattern in their children is that 50% of sons and 50% of daughters are affected (where affected means being a carrier for daughters). ### Final Answer: The expected pattern in their children is that **50% of sons and 50% of daughters are affected**.
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