A sample of chloroform being used as anaesthetic is tested by .

Options

A. Fehling solution
B. Ammoniacal `Cu_(2)Cl_(2)`
C. `AgNO_(3)` solution
D. Boiling with KOH and then adding `AgNO_(3) ` solution

Answer

To determine the purity of a chloroform sample being used as an anesthetic, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Chemical Structure**:
- Chloroform has the molecular formula CHCl3. It is a covalent compound and is known for its anesthetic properties.

2. **Testing for Purity**:
- To test the purity of chloroform, we use **silver nitrate solution (AgNO3)**. This reagent is specifically chosen because it can react with halides to form precipitates.

3. **Understanding the Reaction**:
- If the chloroform is pure, adding silver nitrate will not produce any precipitate. This is because pure chloroform does not release chloride ions (Cl-) in solution.
- In contrast, if the chloroform is impure and contains impurities such as phosgene (COCl2) or hydrochloric acid (HCl), the chloride ions will be present.

4. **Reaction of Impurities**:
- If impurities are present, HCl can dissociate to release Cl- ions. When AgNO3 is added to this mixture, it will react with the Cl- ions to form a white precipitate of silver chloride (AgCl).

5. **Conclusion**:
- The presence of a white precipitate indicates that the chloroform sample is impure and cannot be used as an anesthetic. Conversely, if no precipitate forms, the chloroform is deemed pure and safe for use.

### Final Answer:
The sample of chloroform being used as an anesthetic is tested by **silver nitrate solution (AgNO3)**.

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