Ethylene dichloride and ethylidene chloride are position isomers. Which of the following statement is not applicable to both?

Options

A. Both are dihalogen derivatives
B. Both form the same product with aqueous potash
C. Both form the same product with alcoholic potash
D. Both give Belstein’s test

Answer

To solve the question regarding the position isomers ethylene dichloride and ethylidene chloride, we need to analyze the statements provided and determine which one is not applicable to both compounds.

### Step-by-Step Solution:

1. **Identify the Structure of the Compounds:**
- Ethylene dichloride (1,2-dichloroethane) has the structure:
\[ \text{CH}_2\text{Cl}-\text{CH}_2\text{Cl} \]
- Ethylidene chloride (1-chloro-2-chloroethane) has the structure:
\[ \text{CH}_2\text{Cl}-\text{C}(\text{CH}_3)\text{Cl} \]

2. **Determine the Molecular Formula:**
- Both compounds have the same molecular formula: C2H4Cl2.

3. **Analyze Their Reactivity with Alcoholic KOH:**
- When treated with alcoholic KOH, both compounds can undergo elimination reactions to form alkenes.
- Ethylene dichloride can form ethylene (C2H4) and ethylidene chloride can also form ethylene.

4. **Check for Similarities in Chemical Behavior:**
- Both compounds can undergo nucleophilic substitution and elimination reactions, leading to similar products when treated with alcoholic KOH.

5. **Evaluate the Statements:**
- **Statement A:** Both are dihalogen derivatives. (True for both)
- **Statement B:** Both form the same product with aqueous KOH. (False, as they can form different products)
- **Statement C:** Both give a positive test for the Baeyer test (which tests for unsaturation). (True for both if they form alkenes)

6. **Conclusion:**
- The statement that is not applicable to both compounds is **Statement B**, as they do not necessarily form the same product with aqueous KOH.

### Final Answer:
The statement that is not applicable to both ethylene dichloride and ethylidene chloride is **Statement B**.

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