The product of the reaction of ethyl bromide with dry silver oxide in ethanol is the functional isomer of:

Options

A. A primary alcohol
B. A secondary alcohol
C. A tertiary alcohol
D. All of the above

Answer

To solve the question, we need to analyze the reaction of ethyl bromide (C2H5Br) with dry silver oxide (Ag2O) in ethanol and identify the product, then determine which compound is a functional isomer of that product.

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are ethyl bromide (C2H5Br) and dry silver oxide (Ag2O).

2. **Understand the Reaction**: When ethyl bromide reacts with dry silver oxide, it undergoes a reaction that leads to the formation of diethyl ether. The silver oxide acts as a base and facilitates the elimination of bromine.

3. **Write the Reaction**:
\[ 2 \, C_2H_5Br + Ag_2O \rightarrow C_4H_{10}O + 2 \, AgBr \]
Here, diethyl ether (C4H10O) is formed along with silver bromide (AgBr) as a byproduct.

4. **Identify the Product**: The product of the reaction is diethyl ether (C4H10O).

5. **Determine Functional Isomers**: Now, we need to identify the functional isomers of diethyl ether (C4H10O). Functional isomers are compounds that have the same molecular formula but different functional groups.

6. **Check Possible Isomers**:
- **Primary Alcohol**: C2H5OH (ethanol) can combine with another C2H5 group to form a primary alcohol, C4H10O (butanol).
- **Secondary Alcohol**: Another possibility is a secondary alcohol like isobutanol (C4H10O).
- **Tertiary Alcohol**: Tertiary alcohols like tert-butanol (C4H10O) can also be considered.

7. **Conclusion**: All the compounds mentioned (primary alcohols, secondary alcohols, and tertiary alcohols) have the molecular formula C4H10O and are functional isomers of diethyl ether.

### Final Answer:
The product of the reaction of ethyl bromide with dry silver oxide in ethanol is diethyl ether, which is a functional isomer of primary alcohols, secondary alcohols, and tertiary alcohols with the formula C4H10O.