The product obtained by the hydrolysis of the adduct formed by the reaction of ethyl magnesium iodide with methanal can also be prepared by which of the following reaction?

Options

A. Reduction of ethanal with Na/`C_(2)H_(5)`OH
B. 1-Bromopropane with aqueous KOH
C. Iodoethane with alc. KOH
D. 1-Bromopropane with alc. KOH

Answer

To solve the question regarding the product obtained from the hydrolysis of the adduct formed by the reaction of ethyl magnesium iodide with methanal, we can follow these steps:

### Step 1: Understand the Reaction
The reaction involves ethyl magnesium iodide (C2H5MgI) reacting with methanal (CH2O). This is a Grignard reaction where the Grignard reagent acts as a nucleophile and attacks the carbonyl carbon of methanal.

### Step 2: Formation of the Adduct
When ethyl magnesium iodide reacts with methanal, it forms an adduct (an intermediate compound) known as an alkoxide. The reaction can be represented as:
\[ C2H5MgI + CH2O \rightarrow C2H5CH2OMgI \]
This alkoxide is then hydrolyzed to yield the corresponding alcohol.

### Step 3: Hydrolysis of the Adduct
Upon hydrolysis, the alkoxide reacts with water to produce the final alcohol product:
\[ C2H5CH2OMgI + H2O \rightarrow C2H5CH2OH + Mg(OH)I \]
The final product here is ethanol (C2H5CH2OH).

### Step 4: Identify Alternative Reactions
The question asks for an alternative reaction that can produce the same product (ethanol). One such reaction is the nucleophilic substitution reaction of an alkyl halide with a strong base.

### Step 5: Example of Alternative Reaction
For example, if we take 1-bromopropane (C3H7Br) and treat it with alcoholic KOH, we can achieve a similar product through an SN2 mechanism:
\[ C3H7Br + KOH (alc) \rightarrow C3H7OH + KBr \]
This reaction will also yield propanol (C3H7OH), which is the same product we obtained from the hydrolysis of the adduct.

### Conclusion
Thus, the product obtained by the hydrolysis of the adduct formed by the reaction of ethyl magnesium iodide with methanal can also be prepared by the reaction of 1-bromopropane with alcoholic KOH.

### Final Answer
The correct option is **Option B**.

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