Carbon tetrachloride can be prepared by which of the following reaction?

Options

A. `CS_(2)` with `Cl_(2)` in the presence of `I_(2)`
B. `CS_(2)` with `S_(2)Cl_(2)` in the presence of `I_(2)`
C. (3) `CHCl_(3)` with `Cl_(2)` in the presence of `I_(2)`
D. All of the above

Answer

To determine how carbon tetrachloride (CCl₄) can be prepared, we need to analyze the given reactions one by one.

### Step-by-Step Solution:

1. **Identify the Compounds:**
- Carbon tetrachloride (CCl₄) is the target compound we want to prepare.
- We have three options to evaluate.

2. **Evaluate Option A:**
- The reaction is:
\[ \text{CS}_2 + \text{Cl}_2 \xrightarrow{\text{I}_2} \text{CCl}_4 + \text{S}_2\text{Cl}_2 \]
- This reaction involves carbon disulfide (CS₂) reacting with chlorine (Cl₂) in the presence of iodine (I₂) to produce carbon tetrachloride and disulfur dichloride (S₂Cl₂).
- This reaction can indeed produce CCl₄.

3. **Evaluate Option B:**
- The reaction is:
\[ \text{CS}_2 + \text{S}_2\text{Cl}_2 \xrightarrow{\text{I}_2} \text{CCl}_4 + \text{S}_8 \]
- Here, carbon disulfide reacts with disulfur dichloride in the presence of iodine to yield carbon tetrachloride and octasulfur (S₈).
- This reaction also produces CCl₄.

4. **Evaluate Option C:**
- The reaction is:
\[ \text{CSCl}_3 + \text{Cl}_2 \xrightarrow{\text{I}_2} \text{CCl}_4 + \text{HCl} \]
- In this case, trichloromethane (CSCl₃) reacts with chlorine in the presence of iodine to yield carbon tetrachloride and hydrochloric acid (HCl).
- This reaction also produces CCl₄.

5. **Conclusion:**
- Since all three reactions (A, B, and C) can produce carbon tetrachloride, the correct answer is:
\[ \text{All of the above} \]

### Final Answer:
Carbon tetrachloride can be prepared by all of the following reactions: A, B, and C.

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