Ethylidene chloride on treatement with aq. KOH gives

Options

A. `CH_(3)`CHO
B. `underset(CH_(2)OH)overset(CH_(2)OH)(|)`
C. HCHO
D. `underset("CHO")overset("CHO")(|)`

Answer

To solve the question about the reaction of ethylidene chloride with aqueous KOH, we can follow these steps:

### Step 1: Identify the structure of ethylidene chloride
Ethylidene chloride has the following structure:
\[ \text{CH}_3\text{CCl}_2\text{H} \]
This means it has a carbon chain with two chlorine atoms attached to the same carbon atom.

### Step 2: Write the reaction with aqueous KOH
When ethylidene chloride is treated with aqueous KOH, the chlorine atoms are replaced by hydroxyl (OH) groups. The reaction can be represented as:
\[ \text{CH}_3\text{CCl}_2\text{H} + 2 \text{KOH} \rightarrow \text{CH}_3\text{C(OH)}_2\text{H} + 2 \text{KCl} \]

### Step 3: Dehydration of the intermediate
The product formed in the previous step, which is a diol (with two OH groups), can undergo dehydration. This means that water (H2O) is removed from the molecule:
\[ \text{CH}_3\text{C(OH)}_2\text{H} \rightarrow \text{CH}_3\text{C}=\text{O} + \text{H}_2\text{O} \]

### Step 4: Identify the final product
The final product after dehydration is acetaldehyde, which has the structure:
\[ \text{CH}_3\text{CHO} \]

### Step 5: Compare with the given options
Now we compare the product we obtained (CH3CHO) with the options provided:
- CH3CHO (Acetaldehyde)
- CH2OH
- CH2OH
- HCHO
- CHOCHO

The correct answer is **CH3CHO**, which corresponds to option A.

### Final Answer
Ethylidene chloride on treatment with aqueous KOH gives **CH3CHO** (acetaldehyde).

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