`C_(6) H_(5) N_(2) Cl + "HBF"_(4) overset(Delta)(rarr) C_(6)H_(5)F + N_(2) + BF_(3)` . The reaction is called

Options

A. Balzschiemann reaction
B. Gattermann reaction
C. Sandmeyer’s reaction
D. Swarts reaction

Answer

To determine the name of the reaction given in the question, we will analyze the provided reaction step by step.

### Step 1: Identify the Reactants
The reactants in the given reaction are:
- C₆H₅N₂Cl (which is benzene diazonium chloride)
- HBF₄ (tetrafluoroboric acid)

### Step 2: Understand the Reaction Process
In this reaction, benzene diazonium chloride reacts with HBF₄. The diazonium group (N₂⁺) is a good leaving group, and the reaction involves the replacement of the diazonium group with a fluorine atom.

### Step 3: Formation of Benzene Diazonium Tetrafluoroborate
When benzene diazonium chloride reacts with HBF₄, it forms benzene diazonium tetrafluoroborate:
\[ C₆H₅N₂Cl + HBF₄ \rightarrow C₆H₅N₂BF₄ + HCl \]

### Step 4: Heating the Reaction Mixture
Upon heating, the benzene diazonium tetrafluoroborate decomposes, leading to the release of nitrogen gas (N₂) and the formation of fluorobenzene (C₆H₅F):
\[ C₆H₅N₂BF₄ \xrightarrow{\Delta} C₆H₅F + N₂ + BF₃ \]

### Step 5: Naming the Reaction
The reaction described is known as the **Balz-Schiemann reaction**. This reaction is characterized by the conversion of diazonium salts into aryl fluorides using tetrafluoroboric acid.

### Final Answer
The reaction is called the **Balz-Schiemann reaction**.

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