Which one gives the iodoform test?

Options

A. `CH_(3)`COOH
B. `CH_(3)COOH_(2)`
C. `CH_(3)"COOCH"_(3)`
D. `CH_(3)`COCl

Answer

To determine which compound gives the iodoform test, we need to identify the presence of specific functional groups in the options provided. The iodoform test is positive for compounds that contain either a methyl ketone (CH3CO-) or a secondary alcohol (CH3CHOH-) that can be oxidized to a methyl ketone.

### Step-by-Step Solution:

1. **Understand the Iodoform Test**:
- The iodoform test is used to identify compounds that contain a methyl ketone (CH3CO-) or a secondary alcohol (CH3CHOH-).
- When these compounds are treated with iodine in the presence of a base (like NaOH), they produce iodoform (CHI3).

2. **Analyze Each Option**:
- **Option 1: Acetic Acid (CH3COOH)**
- Contains a CH3CO linkage, but it is connected to an OH group, not an alkyl group.
- **Conclusion**: Does not give a positive iodoform test.

- **Option 2: A compound with CH3COOH (twice)**
- Similar to option 1, it contains a CH3CO linkage but is connected to OH groups.
- **Conclusion**: Does not give a positive iodoform test.

- **Option 3: A compound with CH3CO connected to CH3 and OH**
- Contains a CH3CO linkage, but it is connected to an OH group instead of an alkyl group.
- **Conclusion**: Does not give a positive iodoform test.

- **Option 4: A compound with CH3COCl**
- Contains a CH3CO linkage, but it is connected to a Cl (halide) instead of an alkyl group.
- **Conclusion**: Does not give a positive iodoform test.

3. **Final Conclusion**:
- None of the provided options contain the necessary structure (CH3CO linked to an alkyl group or CH3CHOH linked to an alkyl group) to give a positive iodoform test.

### Answer:
None of the options provided give the iodoform test.