Iodoform is formed on warming `I_2` and `NaOH` with:

Options

A. Acetophenone
B. `CH_(3)OH`
C. `HCOOH`
D. `C_(6)H_(6)`

Answer

To determine which compound forms iodoform when warmed with iodine (I₂) and sodium hydroxide (NaOH), we need to analyze the conditions under which iodoform is produced.

### Step-by-Step Solution:

1. **Understand the Iodoform Test**:
The iodoform test is a qualitative test used to identify methyl ketones and certain aldehydes. The reaction involves the formation of iodoform (CHI₃), which is a yellow precipitate.

2. **Identify the Required Functional Groups**:
The compounds that give a positive iodoform test must contain a methyl group (–CH₃) adjacent to a carbonyl group (C=O). This means we are looking for methyl ketones or the specific aldehyde acetaldehyde (ethanal).

3. **List Possible Candidates**:
From the question, we need to evaluate the compounds provided. The likely candidates for the iodoform test include:
- Acetophenone (C₆H₅COCH₃)
- Acetaldehyde (CH₃CHO)
- Other methyl ketones or secondary alcohols.

4. **Evaluate Each Compound**:
- **Acetophenone (C₆H₅COCH₃)**: This is a methyl ketone and will give a positive iodoform test.
- **Acetaldehyde (CH₃CHO)**: This is the only aldehyde that gives a positive iodoform test.
- **Methanol (CH₃OH)**: This does not have a carbonyl group and will not give a positive test.
- **Carboxylic Acids**: These do not give a positive iodoform test.
- **Benzene (C₆H₆)**: This is an aromatic hydrocarbon and does not contain a carbonyl group.

5. **Conclusion**:
Among the candidates, acetophenone and acetaldehyde are the compounds that can react with I₂ and NaOH to form iodoform. However, since the question asks for warming I₂ and NaOH with a specific compound, the best answer is **Acetophenone**.

### Final Answer:
Iodoform is formed on warming I₂ and NaOH with **Acetophenone**.

---