Carbon-halogen bond is strongest among the following:

Options

A. `CH_(3)`Cl
B. `CH_(3)`Br
C. `CH_(3)`F
D. `CH_(3)`I

Answer

To determine which carbon-halogen bond is the strongest among CH3Cl (methyl chloride), CH3Br (methyl bromide), CH3F (methyl fluoride), and CH3I (methyl iodide), we need to analyze the properties of the halogens involved.

### Step-by-Step Solution:

1. **Identify the Halogens**: The halogens in question are fluorine (F), chlorine (Cl), bromine (Br), and iodine (I). They belong to Group 17 of the periodic table.

2. **Consider Atomic Size**: As we move down the group from fluorine to iodine, the size of the halogen atoms increases. This is due to the addition of electron shells. Therefore, the order of size is:
- Iodine (I) > Bromine (Br) > Chlorine (Cl) > Fluorine (F)

3. **Electronegativity**: Electronegativity is the ability of an atom to attract electrons towards itself. Fluorine is the most electronegative element in the periodic table, followed by chlorine, bromine, and iodine. The order of electronegativity is:
- F > Cl > Br > I

4. **Bond Length and Strength**: The bond length increases with the size of the halogen. A larger atom (like iodine) will form a longer bond with carbon, while a smaller atom (like fluorine) will form a shorter bond. Shorter bonds are generally stronger due to the closer proximity of the bonding electrons.

5. **Analyzing the Bonds**:
- **CH3F**: The bond between carbon and fluorine is short and strong due to fluorine's high electronegativity and small size.
- **CH3Cl**: The bond is longer than CH3F but shorter than CH3Br and CH3I, and it is still relatively strong.
- **CH3Br**: The bond is longer than CH3Cl and weaker.
- **CH3I**: The bond is the longest and weakest due to iodine's large size and lower electronegativity.

6. **Conclusion**: Based on the analysis of bond length and electronegativity, the strongest carbon-halogen bond is found in CH3F (methyl fluoride).

### Final Answer:
The strongest carbon-halogen bond is in CH3F (methyl fluoride).

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