The product of the reaction of chloromethane with sodium sulphide is

Options

A. Dimethyl sulphide
B. Methan thiol
C. Mixture of both the above
D. None of the above

Answer

To determine the product of the reaction of chloromethane (CH3Cl) with sodium sulfide (Na2S), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are chloromethane (CH3Cl) and sodium sulfide (Na2S).

### Step 2: Understand the Reaction Mechanism
Sodium sulfide (Na2S) contains sulfide ions (S^2-), which can react with alkyl halides like chloromethane. The reaction typically involves the substitution of the halogen (chlorine in this case) by the sulfide ion.

### Step 3: Write the Reaction
The general reaction can be represented as:
\[ \text{R-X} + \text{Na}_2\text{S} \rightarrow \text{R}_2\text{S} + \text{NaX} \]
Where R is the alkyl group (in this case, CH3), and X is the halogen (Cl).

### Step 4: Substitute the Reactants into the Equation
For chloromethane (R = CH3, X = Cl):
\[ \text{CH}_3\text{Cl} + \text{Na}_2\text{S} \rightarrow \text{(CH}_3)_2\text{S} + \text{NaCl} \]

### Step 5: Identify the Products
From the reaction, we can see that the products are:
- Dimethyl sulfide (CH3)2S
- Sodium chloride (NaCl)

### Step 6: Finalize the Product
Thus, the final product of the reaction of chloromethane with sodium sulfide is dimethyl sulfide (CH3)2S.

### Conclusion
The product of the reaction of chloromethane with sodium sulfide is **dimethyl sulfide (CH3)2S**.

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