Which of these is obtained as the product when ethanol is treated with conc. `H_(2) so_(4) ` at 413 K ?

Options

A. Ethyl hydrogen sulphate
B. diethyl sulphate
C. ethene
D. diethyl ether

Answer

To determine the product formed when ethanol is treated with concentrated sulfuric acid at 413 K, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is ethanol (C2H5OH).
- The reagent is concentrated sulfuric acid (H2SO4).

2. **Understand the Conditions**:
- The reaction is conducted at a temperature of 413 K.

3. **Reaction Mechanism**:
- When ethanol reacts with concentrated sulfuric acid, the acid donates a proton (H+) to the ethanol, leading to the formation of an oxonium ion (protonated ethanol).
- The oxygen in the ethanol has lone pairs that can attack the proton, resulting in the formation of a carbocation (C2H5+).

4. **Formation of Ether**:
- Another molecule of ethanol can then attack the carbocation. The lone pair of electrons on the oxygen of the second ethanol molecule will bond with the carbocation, leading to the formation of diethyl ether (C2H5OC2H5) and the release of a water molecule.

5. **Final Product**:
- The final product of the reaction is diethyl ether (C2H5OC2H5), along with the evolution of water.

### Conclusion:
- The product obtained when ethanol is treated with concentrated sulfuric acid at 413 K is diethyl ether (C2H5OC2H5).