`CH_(3)"COOH" underset(Br_(2))overset("AgOH")(rarr)"[A]" overset("AgCN")` [B] `overset("HOH")(rarr)` [ C] + [D], in reaction [C] & [D] are

Options

A. `(CH_(3))_(2) NH + H_(2)`O
B. `(CH_(3))_(2)` NH + HCOOH
C. `CH_(3)NH_(2) + ` HCOOH
D. `CH_(3)"COOH" + NH_(3)`

Answer

To solve the given reaction step by step, we will analyze the transformations occurring in the reaction sequence. The reaction involves acetic acid (CH₃COOH), bromine (Br₂), silver hydroxide (AgOH), and silver cyanide (AgCN), leading to the formation of compounds A, B, C, and D.

### Step 1: Reaction of Acetic Acid with Bromine and Silver Hydroxide
1. **Starting Compound**: Acetic acid (CH₃COOH).
2. **Reagents**: Br₂ and AgOH.
3. **Reaction**: The bromine reacts with acetic acid in the presence of silver hydroxide, leading to the formation of bromoacetic acid (CH₂BrCOOH) and the removal of silver bromide (AgBr) as a byproduct.

**Chemical Equation**:
\[ \text{CH}_3\text{COOH} + \text{Br}_2 + \text{AgOH} \rightarrow \text{CH}_2\text{BrCOOH} + \text{AgBr} + \text{H}_2\text{O} \]

**Compound A**: Bromoacetic acid (CH₂BrCOOH).

### Step 2: Reaction of Compound A with Silver Cyanide
1. **Compound A**: Bromoacetic acid (CH₂BrCOOH).
2. **Reagent**: AgCN.
3. **Reaction**: Bromoacetic acid reacts with silver cyanide, replacing the bromine atom with a cyanide group, forming cyanoacetic acid (CH₂(CN)COOH) and precipitating silver bromide.

**Chemical Equation**:
\[ \text{CH}_2\text{BrCOOH} + \text{AgCN} \rightarrow \text{CH}_2(\text{CN})\text{COOH} + \text{AgBr} \]

**Compound B**: Cyanoacetic acid (CH₂(CN)COOH).

### Step 3: Hydrolysis of Compound B
1. **Compound B**: Cyanoacetic acid (CH₂(CN)COOH).
2. **Reagent**: Water (H₂O).
3. **Reaction**: Hydrolysis of cyanoacetic acid leads to the formation of acetic acid (CH₃COOH) and ammonia (NH₃) as the cyanide group is converted into an amine.

**Chemical Equation**:
\[ \text{CH}_2(\text{CN})\text{COOH} + 2\text{H}_2\text{O} \rightarrow \text{CH}_3\text{COOH} + \text{NH}_3 + \text{CO}_2 \]

**Compounds C and D**:
- Compound C: Acetic acid (CH₃COOH).
- Compound D: Ammonia (NH₃).

### Final Summary
- **Compound A**: Bromoacetic acid (CH₂BrCOOH).
- **Compound B**: Cyanoacetic acid (CH₂(CN)COOH).
- **Compound C**: Acetic acid (CH₃COOH).
- **Compound D**: Ammonia (NH₃).

### Answer:
The compounds C and D are acetic acid (CH₃COOH) and ammonia (NH₃), respectively.

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