Hydrogen bonding is not shown by

Options

A. Water
B. Glycerol
C. Hydrogen fluoride
D. Hydrogen Sulphide

Answer

To determine which of the given substances does not exhibit hydrogen bonding, we need to analyze each option based on the criteria for hydrogen bonding.

### Step-by-Step Solution:

1. **Understanding Hydrogen Bonding**:
- Hydrogen bonding occurs when a hydrogen atom is covalently bonded to a highly electronegative atom (like nitrogen, oxygen, or fluorine) and is attracted to a lone pair of electrons on another electronegative atom.

2. **Analyzing Each Option**:
- **Water (H2O)**:
- Water has two hydrogen atoms bonded to oxygen, which is highly electronegative. Oxygen has lone pairs that can interact with hydrogen atoms from other water molecules. Therefore, water exhibits hydrogen bonding.

- **Glycerol (C3H8O3)**:
- Glycerol contains multiple hydroxyl (–OH) groups. Each –OH group has a hydrogen atom bonded to oxygen, which is electronegative, and oxygen also has lone pairs. Hence, glycerol can form hydrogen bonds.

- **Hydrogen Fluoride (HF)**:
- In HF, hydrogen is bonded to fluorine, which is highly electronegative. Fluorine has lone pairs that can interact with hydrogen atoms from other HF molecules. Thus, hydrogen fluoride also exhibits hydrogen bonding.

- **Hydrogen Sulfide (H2S)**:
- In H2S, hydrogen is bonded to sulfur. Sulfur is not as electronegative as nitrogen, oxygen, or fluorine, and it is larger in size. This means it does not have the strong attraction necessary for hydrogen bonding. Therefore, hydrogen sulfide does not exhibit hydrogen bonding.

3. **Conclusion**:
- Based on the analysis, the substance that does not show hydrogen bonding is **Hydrogen Sulfide (H2S)**.

### Final Answer:
**Hydrogen bonding is not shown by Hydrogen Sulfide (H2S).**

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