For a process such as `I_(2)(s)hArr I_(2)(g)` if equilibrium is established at 300 K and the heat of sublimation of iodine is 60.2 kJ/mole then what will be entropy change of sublimation ?

Explanation

To find the entropy change of sublimation for the process \( I_2(s) \rightleftharpoons I_2(g) \) at equilibrium, we can use the relationship between Gibbs free energy, enthalpy, and entropy. Here’s a step-by-step solution:

### Step 1: Understand the relationship between Gibbs free energy, enthalpy, and entropy.
At equilibrium, the change in Gibbs free energy (\( \Delta G \)) is zero. The relationship is given by:
\[ \Delta G = \Delta H - T \Delta S \]
Since \( \Delta G = 0 \) at equilibrium, we can rearrange this equation to find:
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