Home
Class 12
CHEMISTRY
If S + O(2) rightarrow SO(2), DeltaH = -...

If `S + O_(2) rightarrow SO_(2), DeltaH = - 298.2 kJ`
`SO_(2) + 1/2O_(2) rightarrow SO_(3), Delta H = -98.7 kJ`
`SO_(3) + H_(2)O rightarrow H_(2)SO_(4), Delta H = -130.2 kJ`
`H_(2) + 1/2O_(2) rightarrow H_(2)O, Delta H = -287.3 kJ`

A

`-433.7 kJ`

B

`-650.3 kJ`

C

`+320.5 kJ`

D

`-813.9 kJ`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL THERMODYNAMICS

    VMC MODULES ENGLISH|Exercise IN - CHAPTER EXERCISE - G|10 Videos

  • CHEMICAL THERMODYNAMICS

    VMC MODULES ENGLISH|Exercise IN - CHAPTER EXERCISE - H|10 Videos

  • CHEMICAL THERMODYNAMICS

    VMC MODULES ENGLISH|Exercise IN - CHAPTER EXERCISE - E|10 Videos

  • CHEMICAL KINETICS

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|52 Videos

  • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

    VMC MODULES ENGLISH|Exercise JEE ADVANCE (ARCHIVE)|30 Videos

Similar Questions

Explore conceptually related problems

underline(S)O_(3)+H_(2)O to H_(2)SO_(4)

underline(S)O_(3)+H_(2)O to H_(2)SO_(4)

If S+O_(2)toSO_(2),DeltaH=-298.2 " kJ" " mole"^(-1) SO_(2)+(1)/(2)O_(2)toSO_(3)DeltaH=-98.7 " kJ" " mole"^(-1) SO_(3)+H_(2)OtoH_(2)SO_(4),DeltaH=-130.2 " kJ" " mole"^(-1) H_(2)+(1)/(2)O_(2)toH_(2)O,DeltaH=-287.3 " kJ" " mole"^(-1) the enthlapy of formation of H_(2)SO_(4) at 298 K will be

If S+O_(2)toSO_(2),DeltaH=-298.2 " kJ" " mole"^(-1) SO_(2)+(1)/(2)O_(2)toSO_(3)DeltaH=-98.7 " kJ" " mole"^(-1) SO_(3)+H_(2)OtoH_(2)SO_(4),DeltaH=-130.2 " kJ" " mole"^(-1) H_(2)+(1)/(2)O_(2)toH_(2)SO_(4),DeltaH=-287.3 " kJ" " mole"^(-1) the enthlapy of formation of H_(2)SO_(4) at 298 K will be

If S+O_(2)toSO_(2),DeltaH=-298.2 " kJ" " mole"^(-1) SO_(2)+(1)/(2)O_(2)toSO_(3)DeltaH=-98.7 " kJ" " mole"^(-1) SO_(3)+H_(2)OtoH_(2)SO_(4),DeltaH=-130.2 " kJ" " mole"^(-1) H_(2)+(1)/(2)O_(2)toH_(2)SO_(4),DeltaH=-287.3 " kJ" " mole"^(-1) the enthlapy of formation of H_(2)SO_(4) at 298 K will be

DeltaS_("surr") " for " H_(2) + 1//2O_(2) rarr H_(2)O, DeltaH -280 kJ at 400K is

underline(S)O_(2)+H_(2)O to H_(2)SO_(3)

underline(S)O_(2)+H_(2)O to H_(2)SO_(3)

If {:(SO_(2)+1/2O_(2) rarr SO_(3),DeltaH = -98.7 kJ),(SO_(3)+H_2O rarr H_(2)SO_(4),DeltaH = -130.2 kJ),(H_(2)+1/2O_(2) rarr H_2O , Delta H = -287.3 kJ),(S + H_2 + 2O_(2) rarr H_2SO_4, DeltaH = -814.4 kJ):} Then enthaply of SO_(2) at 298 K is:

2Zn + O_(2) rightarrow 2ZnO, Delta G^(@) = -616 J 2Zn + S_(2) rightarrow 2ZnS, Delta G^(@) = -293 J S_(2) + 2O_(2) rightarrow 2SO_(2), Delta G^(@) = -408 J Delta G^(@) for the following reaction 2ZnS + 3O_(2) rightarrow 2ZnO+ 2 SO_(2) is