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The value of K(c) for the reaction: H(2)...

The value of `K_(c)` for the reaction: `H_(2)(g)+I_(2)(g) hArr 2HI (g)` is 48 at 773 K. If one mole of `H_(2)`, one mole of `I_(2)` and three moles of HI are taken in a 1L falsk, find the concentrations of `I_(2)` and HI at equilibrium at 773 K.

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To solve the problem step by step, we will follow these instructions: ### Step 1: Write the balanced chemical equation and the expression for \( K_c \) The balanced chemical equation is: \[ H_2(g) + I_2(g) \rightleftharpoons 2HI(g) \] The expression for the equilibrium constant \( K_c \) is given by: ...
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The value of K_(c) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) is 64 at 773K . If one "mole" of H_(2) , one mole of I_(2) , and three moles of HI are taken in a 1 L flask, find the concentrations of I_(2) and HI at equilibrium at 773 K .

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