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The equilibrium constant for the reactio...

The equilibrium constant for the reaction
`H_(2)(g)+S(s) hArr H_(2)S(g)`
is `18.5` at `925 K` and `9.25` at `1000 K`, respectively. Calculate the enthalpy of the reaction.

Text Solution

Verified by Experts

Using the relation
`"log"(K_(2))/(K_(1))=(DeltaH)/(2.303R)[(T_(2)-T_(1))/(T_(1)T_(2))]`
`"log"(9.25)/(18.5)=(DeltaH)/(2.303xx8.314)xx(75)/(925xx1000)`
`DeltaH= -71080.57 J" mol"^(-1)`
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