The `pK_(a)` for acid A is greater than `pK_(a)` for acid B, the strong acid is :-

Options

A. Acid B
B. Acid A
C. Both A and B
D. Neither A nor B

Answer

To determine which acid is stronger based on the given pKa values, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Relationship Between pKa and Ka**:
- The dissociation constant (Ka) of an acid is a measure of its strength. A higher Ka value indicates a stronger acid because it means the acid dissociates more in solution.
- The pKa is defined as the negative logarithm of Ka:
\[ pKa = -\log(Ka) \]
- Therefore, there is an inverse relationship between pKa and acid strength: a lower pKa value corresponds to a stronger acid.

2. **Analyze the Given Information**:
- The problem states that the pKa of acid A is greater than the pKa of acid B:
\[ pKa_A > pKa_B \]

3. **Interpret the pKa Values**:
- Since pKa_A is greater than pKa_B, it implies that:
\[ Ka_A < Ka_B \]
- This means that acid A has a lower dissociation constant than acid B.

4. **Determine the Stronger Acid**:
- Since acid B has a higher Ka value (and thus a lower pKa value), it is the stronger acid compared to acid A.

5. **Conclusion**:
- Therefore, the stronger acid between acid A and acid B is acid B.

### Final Answer:
The strong acid is **acid B**.

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