Home
Class 12
CHEMISTRY
Degree of dissociation of 0.1 NCH(3) COO...

Degree of dissociation of 0.1 `NCH_(3) COOH` is Given `K_("Acid") = 1 xx 10^(-5)`

A

`10^(-5)`

B

`10^(-4)`

C

`10^(-3)`

D

`10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
4
Promotional Banner

Topper's Solved these Questions

  • IONIC EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise IN - CHAPTER EXERCISE - D|10 Videos
  • IONIC EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise IN - CHAPTER EXERCISE - E|10 Videos
  • IONIC EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise IN - CHAPTER EXERCISE - B|10 Videos
  • INTRODUCTION TO ORGANIC CHEMISTRY

    VMC MODULES ENGLISH|Exercise JEE ADVANCED ARCHIVE|81 Videos
  • JEE MAIN - 5

    VMC MODULES ENGLISH|Exercise PART II : CHEMISTRY (SECTION - 2)|5 Videos

Similar Questions

Explore conceptually related problems

The degree of dissociation of 0.1 N CH_3 COOH is (given K_a=1 xx 10^(-5) ) approximately

The degree of dissociation of 0.1N CH_(3)COOH is (K_(a)= 1xx10^(-5))

Which of the following solutions added to 1L of a 0.01 M CH_(3)COOH solution will cause no change in the degree of dissociation of CH_(3)COOH and pH of the solution ? (K_(a)=1.6xx10^(-5) for CH_(3)COOH)

Degree of dissociation of 0.1 molar acetic acid at 25^(@)C (K_(a) = 1.0 xx 10^(-5)) is

The degree of dissociation of 0.1 M acetic acid is 1.4 xx 10^(-2) . Find out the pKa?

If degree of dissociation of 2M CH_3 COOH is 10% then degree of dissociation of this acetic acid in 3 Molar CH_3 COONa solution will be

What is the concentration of CH_(3)COOH which can be added to 0.5M HCOOH solution so that dissociation of both is same. K_(CH_(3)COOH) = 1.8 xx 10^(-5), K_(HCOOH) = 2.4 xx 10^(-4)

The dissociation constant of 0.01 M CH_3COOH "is" 1.8 xx 10^(-5) , then calculate the dissociation constant of its conjugate base (CH_3COO^-)

The dissociation constants for HCOOH " and " CH_(3)COOH " are " 2.1 xx 10^(-4) " and " 1.8 xx 10^(-5) respectively. Calculate the relative strengths of the acids .

Calculate pH of the mixture ( 50 mL of 0.05 M NH_(4)OH + 50 mL of 0.05 M CH_(3)COOH ) Given that K_(a) = 1.8 xx 10^(-5) , and K_(b) = 1.8 xx10^(-5)