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The pK(a) of a weak acid is 4.8 . What s...

The `pK_(a)` of a weak acid is `4.8` . What should be the ratio of [Acid]/[Salt] of a buffer if `pH = 5 .8` is required

A

10

B

`0.1`

C

1

D

2

Text Solution

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The correct Answer is:
To solve the problem, we will use the Henderson-Hasselbalch equation, which relates the pH of a buffer solution to the pKa of the weak acid and the ratio of the concentrations of the salt (conjugate base) and the acid. ### Step-by-Step Solution: 1. **Write the Henderson-Hasselbalch Equation:** \[ \text{pH} = \text{pK}_a + \log\left(\frac{[\text{Salt}]}{[\text{Acid}]}\right) \] 2. **Substitute the Given Values:** - Given: \(\text{pK}_a = 4.8\) - Required: \(\text{pH} = 5.8\) \[ 5.8 = 4.8 + \log\left(\frac{[\text{Salt}]}{[\text{Acid}]}\right) \] 3. **Rearrange the Equation:** \[ \log\left(\frac{[\text{Salt}]}{[\text{Acid}]}\right) = 5.8 - 4.8 \] \[ \log\left(\frac{[\text{Salt}]}{[\text{Acid}]}\right) = 1 \] 4. **Convert from Logarithmic to Exponential Form:** \[ \frac{[\text{Salt}]}{[\text{Acid}]} = 10^1 = 10 \] 5. **Find the Ratio of Acid to Salt:** - We need to find \(\frac{[\text{Acid}]}{[\text{Salt}]}\): \[ \frac{[\text{Acid}]}{[\text{Salt}]} = \frac{1}{10} = 0.1 \] ### Final Answer: The ratio of \([\text{Acid}]/[\text{Salt}]\) is \(0.1\).
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