CdO has NaCl structures with density `8.27 g//c c `.If the ionic radius of `O^(2)` is `1.24 Å` , determine ionic radius of `Cd^(2+)` :

Explanation

`"Density"=(("No.of formula units")xx("Molecular weight of compound")xx1.67xx10^(-27)kg)/("Volume of unit cell")`
`8.27xx10^(3)kg//m^(3)=((4)xx128.41xx1.67xx10^(-27))/(a^3)rArra=4.70overset(@)(A)`
We have, `2[r_(Cd^(2+))+r_(O^(2-))]=a`
`rArr" "r_(Cd^(2+))+1.24=2.35" "rArr" "r_(Cd^(2+))=1.11overset(@)(A)`