Silver has a cubic unit cell with a cell edge of 408 pm. Its density is 10.6 g `cm^(-3)`. How many atoms of silver are there in the unit cell? What is the structure of silver?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the Volume of the Unit Cell
The volume \( V \) of a cubic unit cell can be calculated using the formula:
\[ V = a^3 \]
where \( a \) is the edge length of the unit cell. Given that \( a = 408 \) pm, we first convert this to centimeters:
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