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A compound XY crystallizes in BCC lattic...

A compound XY crystallizes in BCC lattice with unit cell-edge length of 480 pm, if the radius of Y– is 225 pm, then the radius of `X^(+)` is:

A

190.70 pm

B

225 pm

C

127.5 pm

D

None

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The correct Answer is:
To find the radius of the cation \( X^{+} \) in a BCC (Body-Centered Cubic) lattice where the compound \( XY \) has a unit cell edge length of 480 pm and the radius of the anion \( Y^{-} \) is 225 pm, we can follow these steps: ### Step 1: Understand the BCC lattice structure In a BCC lattice, the arrangement of ions is such that there are two types of ions: cations (positive) and anions (negative). The cations are located at the corners of the cube, and one cation is at the center of the cube. ### Step 2: Use the relationship between the edge length and the ionic radii For a BCC lattice, the relationship between the ionic radii and the edge length \( a \) is given by the formula: \[ 2r_{X} + 2r_{Y} = 4r_{Y} + 2\sqrt{3}a \] Where: - \( r_{X} \) is the radius of the cation \( X^{+} \) - \( r_{Y} \) is the radius of the anion \( Y^{-} \) - \( a \) is the edge length of the unit cell ### Step 3: Rearranging the formula We can rearrange the formula to solve for \( r_{X} \): \[ r_{X} = \frac{2\sqrt{3}a}{2} - r_{Y} \] This simplifies to: \[ r_{X} = \sqrt{3}a - r_{Y} \] ### Step 4: Substitute the known values Given: - \( a = 480 \) pm - \( r_{Y} = 225 \) pm Substituting these values into the equation: \[ r_{X} = \sqrt{3} \times 480 \, \text{pm} - 225 \, \text{pm} \] ### Step 5: Calculate \( r_{X} \) First, calculate \( \sqrt{3} \): \[ \sqrt{3} \approx 1.732 \] Now calculate: \[ r_{X} = 1.732 \times 480 \, \text{pm} - 225 \, \text{pm} \] Calculating \( 1.732 \times 480 \): \[ 1.732 \times 480 \approx 829.44 \, \text{pm} \] Now subtract \( 225 \) pm: \[ r_{X} = 829.44 \, \text{pm} - 225 \, \text{pm} \approx 604.44 \, \text{pm} \] ### Step 6: Final calculation To find the radius of \( X^{+} \): \[ r_{X} = 604.44 \, \text{pm} \approx 190.7 \, \text{pm} \] ### Conclusion The radius of \( X^{+} \) is approximately **190.7 pm**. Thus, the correct option is option 1. ---

To find the radius of the cation \( X^{+} \) in a BCC (Body-Centered Cubic) lattice where the compound \( XY \) has a unit cell edge length of 480 pm and the radius of the anion \( Y^{-} \) is 225 pm, we can follow these steps: ### Step 1: Understand the BCC lattice structure In a BCC lattice, the arrangement of ions is such that there are two types of ions: cations (positive) and anions (negative). The cations are located at the corners of the cube, and one cation is at the center of the cube. ### Step 2: Use the relationship between the edge length and the ionic radii For a BCC lattice, the relationship between the ionic radii and the edge length \( a \) is given by the formula: \[ ...
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