The product "A" in the following reaction is `: CH_(3)-CO-CH_(2)COOC_(2)H_(5)underset( H_(2)O)overset( NaOH) ( rarr) A`

Options

A. `CH_(3)COOH`
B. `C_(2)H_(5)OH`
C. `CH_(3)COCH_(3)`
D. `C_(2)H_(5)CHO`

Answer

To solve the problem, we need to analyze the reaction given in the question. The compound CH₃-CO-CH₂-COOC₂H₅ is treated with NaOH and water (H₂O). This suggests that we are dealing with a reaction that involves hydrolysis or a similar process.

### Step-by-Step Solution:

1. **Identify the Structure of the Reactant**:
The compound CH₃-CO-CH₂-COOC₂H₅ can be broken down as follows:
- CH₃-CO- represents an acetyl group (C2H3O).
- CH₂-COO- represents an ethyl ester group (C2H5O).
This compound is a β-keto ester.

2. **Recognize the Type of Reaction**:
The presence of NaOH and water indicates that a hydrolysis reaction is taking place. In this case, it is likely that the β-keto ester undergoes hydrolysis to yield a carboxylic acid and an alcohol.

3. **Write the Reaction**:
The reaction can be represented as:
\[ CH₃-CO-CH₂-COOC₂H₅ + NaOH + H₂O \rightarrow A \]
where A is the product formed after hydrolysis.

4. **Determine the Products**:
The hydrolysis of the β-keto ester will yield:
- A carboxylic acid (from the ester part).
- An alcohol (from the hydrolysis of the ester).
Specifically:
- The ethyl group (C₂H₅) will be converted to ethanol (C₂H₅OH).
- The ketone part (CH₃-CO-) will remain as acetone (CH₃-CO-).

5. **Final Product**:
The final product A will consist of the carboxylic acid derived from the ester and the alcohol. Therefore, A can be represented as:
\[ A = CH₃-COOH + C₂H₅OH \]
This indicates that A contains both acetic acid (from the hydrolysis of the ester) and ethanol.

### Conclusion:
The product "A" is a mixture of acetic acid (CH₃COOH) and ethanol (C₂H₅OH).

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