Acetaldehyde reacts with `C_(2) H_(3) MgCl` the final product is

Options

A. An aldehyde
B. A ketone
C. A primary alcohol
D. A secondary alcohol

Answer

To solve the problem of what product is formed when acetaldehyde reacts with C2H5MgCl (a Grignard reagent), we can follow these steps:

### Step 1: Identify the Reactants
We have acetaldehyde (CH3CHO) and the Grignard reagent (C2H5MgCl).

### Step 2: Understand the Reaction Mechanism
Grignard reagents react with carbonyl compounds (like aldehydes and ketones) to form alcohols. In this case, acetaldehyde is an aldehyde.

### Step 3: Nucleophilic Attack
The Grignard reagent (C2H5-) acts as a nucleophile and attacks the electrophilic carbon of the carbonyl group in acetaldehyde. The reaction can be represented as follows:
- The nucleophile (C2H5-) attacks the carbonyl carbon (C=O) of acetaldehyde.

### Step 4: Formation of the Intermediate
This nucleophilic attack leads to the formation of a tetrahedral intermediate. The structure of the intermediate can be represented as:
- CH3C(OH)(C2H5)MgCl.

### Step 5: Protonation
When water (or a dilute acid) is added to the reaction mixture, the intermediate is protonated. The oxygen atom in the intermediate will attract a proton (H+) from water, leading to the formation of an alcohol.

### Step 6: Final Product
The final product after the protonation step is:
- CH3C(OH)(C2H5), which is a secondary alcohol because the carbon bearing the hydroxyl group (OH) is attached to two other carbon atoms.

### Conclusion
Thus, the final product of the reaction between acetaldehyde and C2H5MgCl is a secondary alcohol.

### Final Answer
The final product is a secondary alcohol.

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