A particle starts from rest and has an acceleration of `2 ms^(–2)` for 10 s. After that, it travels for 30 s with constant speed and then undergoes a retardation of `4 ms^(–2)` and comes to rest. Calculate the total distance covered by the particle.

Explanation

To solve the problem step by step, we will break down the motion of the particle into three distinct phases: acceleration, constant speed, and retardation.

### Step 1: Calculate the distance during acceleration

The particle starts from rest and accelerates at `2 m/s²` for `10 seconds`.

- Initial velocity (u) = 0 m/s (starts from rest)
- Acceleration (a) = 2 m/s²
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