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A ball is dropped from the top of a buil...

A ball is dropped from the top of a building. The ball takes `0.5s` to fall the `3m` length of a window some distance from the to of the building. If the speed of the ball at the top and at the bottom of the window are `v_(T)` and `v_(T)` respectively, then `(g=9.8m//s^(2))`

Text Solution

Verified by Experts

The distance needed to reach this speed is `h=(v_(A)^(2))/(2g) =((3.55)^(2))/(2(9.8)) =0.64 m`
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